usb gemtek radio 21 program download

In this case, as every point in the curve is at an equal distance from the YP, its plan will be a straight line a'b', No. 2, parallel to the IL, and its projected length will equal the distance between projectors let fall from its ends A and B into the HP. Its side elevation will also be a straight line ab, at right angles to the IL, for as every point in it is equi-distant from the YP, it will coincide with or lie in a plane which we are told in the problem is parallel to the YP, and therefore perpendicular to the HP. To find the elevation of the line AB when the plane in which it lies makes any given angle with the YP, proceed as follows : Choose any convenient points other than its two ends in the curve as 1, 2, 3, 4, No. 1. Through these let fall projectors into the MECHANICAL AND ENGINEERING DRAWING I 87 88 FIRST PRINCIPLES OF HP to cut ab', No. 2, the plan of AB in the points 1', 2', 3', 4'. At b', in this plan, draw a line making with ab' an angle equal to that say 45 the plane containing the curve line is to make with the YP Transfer by arcs struck from b' the points 1', 2', 3', 4' in ab' to a"b', and through these draw projectors into the YP, cutting those drawn through A, 1, 2, 3, 4, No. 1, to the datum line CB in c, d, e,f, g ; a curve drawn through these points, as shown, will be the elevation required. In this way the elevation of any curved line lying in a plane making any angle with the YP, may be found, for the line, or the plane in which it is supposed to lie, may be assumed to rotate round the